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An 89 N box of oranges is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 1.20 m/s each second. The push force has a horizontal component of 25 N and a vertical component of 30 N downward. Calculate the coefficient of kinetic friction between the box and floor.

  • physics -

    Fb = 89 N. @ 0 deg. = Force of box.
    Fp = 89*sin(0) = 0 = Force parallel to
    the floor.
    Fv = 89*cos(0) = 89 N. = Force perpendicular to the floor.

    mg = 89,
    m=89/g = 89/9.8 = 9.08 kg=Mass of box.

    Fn = Fap-Fp-Fk = ma,
    25-0-Fk = 9.08*-1.2 = -10.9,
    -Fk = -10.9-25 = -35.9,
    Fk = 35.9 N. = Force of kinetic friction.

    u(89+30) = 35.9
    119u = 35.9,
    u = 0.30 = Coefficient of kinetic friction.

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