Calculus
posted by Untamed .
1/a+1 + 1/a1
I solved this out by multiplying the (a+1) by (a1) and multiplying (a1) with (a+1) To get (a+1)(a1) as the denominator. Then I did the same with the numerators and got this:
1(a1) + 1(a+1)/(a+1)(a1)
And I got 2a/(a+1)(a1)
But still sometimes this process confuses me so could someone please explain and solve this problem for me step by step so I actually understand it well? Thanks.

1/(a+1) + (1/a1)
(a1)/[(a+1)(a1)] + (a+1)/[(a+1)(a1)]
[ a1+a+1 ] / [(a+1)(a1)]
2a / (a^21)
so I agree with you
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