Geometry Question
posted by Jenn .
B is the midpoint of segment AC and D is the midpoint of segment CE. Solve for x, given BD=3x+5 and AE=4x+20.
Sorry I couldn't get the link for the picture but, the diagram is a picture of a triangle with a C at the top, and A and E on
the bottom angles, with segment BD going through the middle of the triangle.
Thank You ^0^

triangle BCD is similar to triangle ACE (side, angle C, side)
AC = 2 BC
therefore AE = 2 BD
therefore
4x+20 = 2 (3x+5) solve that 
Thank You So Much! ^0^

What's the answer?

What's the answer?

whats answer

What's the answer?

BD= 1/2 AE.
So the real equation is 6x+10=4x+20
isolate the variable and you will get your answer.
the answer is x=5