How much work is needed to stop a 20g bullet moving with speed of 150m/s
(1/2) m v^2 = (1/2).020*22500
To determine the amount of work needed to stop a bullet, we can use the concept of kinetic energy.
The formula for kinetic energy is given by:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the mass of the bullet is 20 grams, we need to convert it to kilograms by dividing by 1000 (since 1 kilogram = 1000 grams):
mass = 20 grams ÷ 1000 = 0.02 kilograms
The velocity of the bullet is given as 150 m/s.
Now, we can use the formula for kinetic energy to calculate the initial kinetic energy of the bullet:
Initial Kinetic Energy = (1/2) * mass * velocity^2
Initial Kinetic Energy = (0.5) * 0.02 kg * (150 m/s)^2
Simplifying the equation:
Initial Kinetic Energy = 0.5 * 0.02 * 150^2
Initial Kinetic Energy = 0.5 * 0.02 * 22500
Initial Kinetic Energy = 225 Joules
Therefore, the amount of work required to stop the bullet is equal to the initial kinetic energy, which is 225 Joules.