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How many liters of 1.00 M HCl must be added to 50.0 ml of 0.500 M HCl to give a solution whose
concentration is 0.750 M?

  • chem -

    moles = M x L
    moles soln1 + moles soln2 = moles soln 3
    (0.500M*0.0500L) + (1.00M*xL) = 0.750M*(0.0500+xL)
    Solve for xL.
    If I didn't make a math error the answer is 50 mL.

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