What are the the missing reactants for the double-displacement reaction that produces PF5 and AsCl3 ?
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PCl3+AsF5
PCl5 abd AsF3
To determine the missing reactants for a double-displacement reaction, we need to balance the chemical equation first. Let's consider the reaction:
PF3 + AsCl5 → PF5 + ?
In this reaction, we have PF3 and AsCl5 as the known reactants, and PF5 as the known product. To balance the equation, we need to ensure that the number of each type of atom is the same on both sides.
First, let's balance the phosphorus (P) atoms:
On the left side: 1 P atom in PF3
On the right side: 1 P atom in PF5
Next, let's balance the chlorine (Cl) atoms:
On the left side: 5 Cl atoms in AsCl5
On the right side: 0 Cl atoms (since PF5 does not contain chlorine)
Since we don't have any chlorine on the right side of the equation, we need another compound that contains chlorine. One compound we can use is PCl5 (phosphorus pentachloride).
The balanced equation now becomes:
PF3 + AsCl5 → PF5 + PCl5
Therefore, the missing reactant in this double-displacement reaction that produces PF5 and AsCl3 is PCl5.
...........==> PF5 AsCl3
In a double displacement, + of one goes with - of the other, then - of other goes with + of first. Here is how it works.
P(the +) must have started with - of the other (Cl3) and that is PCl3. Then As(+) must have started with F(-) and that is AsF5. The reaction is
PCl3 + AsF5 ==> PF5 + AsCl3