17. A 60.-kilogram student climbs a ladder a vertical distance of 4.0 meters in 8.0 seconds. Approximately how much total work is done against gravity by the student during the climb?
2.4
Fs = mg = 60 kg * 9.8 N./kg = 588 N. =
Weight or force of student.
W = F*d = 588 * 4 = 2352 Joules.
FS = MG = 60Kg X 9.8 N/Kg x 4
= 588 x 4= 2352 or 2400 Joules
LMAO HE ASKED THE QUESTION IN 2012
To find the total work done against gravity by the student during the climb, we can use the formula:
Work = force x distance
The force can be calculated using the formula:
Force = mass x gravity
Where:
mass = 60 kg (given)
gravity = 9.8 m/s^2 (acceleration due to gravity)
First, let's calculate the force:
Force = mass x gravity
Force = 60 kg x 9.8 m/s^2
Force = 588 N
Now, we can calculate the work done using the formula:
Work = force x distance
Work = 588 N x 4.0 m
Work = 2352 Joules
Therefore, the approximate total work done against gravity by the student during the climb is 2352 Joules.