What is the y-intersept of a line with the equation 10y= 5x + 20?

y intercept happens when x = 0

10 y = 20
y = 2

Now with a question like that why were you answering the Calculus question below this one?

This is not a calculas question, this is an ALGEBRA 1 question it is for my review. That answer you gave me is not right.

You must need a tutor. Damon correctly answered you, and it is correct. The y intercept is when x=0, and it is (0,2)

To find the y-intercept of a line, you need to know the equation of the line. In this case, the equation given is 10y = 5x + 20.

The y-intercept is the point where the line intersects the y-axis, which means the value of x is 0 at this point.

To find the y-intercept, substitute 0 for x in the equation and solve for y.

10y = 5(0) + 20
10y = 0 + 20
10y = 20

Now, divide both sides of the equation by 10 to isolate y.

y = 20/10
y = 2

Therefore, the y-intercept of the line with the equation 10y = 5x + 20 is 2.

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