# intermediate algebra

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0.3x + 0.2y=5, 0.5x + 0.4y=11 using the substitution method

• intermediate algebra -

.3x + .2y = 5
so
3x + 2y = 50
y = 25 - 3x/2

.5x + .4y = 11
5x + 4y = 110
5x + 4(25 - 3x/2) = 110
5x + 100 - 6x = 110
-x = 10

x = -10
y = 40

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