maths
posted by joi .
A bag contained a number of 20cents, 50cents and $1 coins. 1/3 of the 20cents coins is equal to 2/3 of the 50cents coins. There are 3/5 as many 50cents coins as $1 coins. If the total value of these coins is $23.10, how many coins are there altogether ?
(nonalgebra solution request pls)

1/3 T= 2/3F
3/5 D=F
.2T+.5F+1D=23.10
Can you take if from there?
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