Calculus
posted by Untamed .
Simplify. State the nonpermissible values.
4a^21/4a^216*2a/2a1
This is what I did to try and solve it out:
(2a+1)(2a1)/(2a+4)(2a4)*2a/(2a1)
I cancelled out the (2a1)'s and don't get how to solve.
I'm supposed to get the answer :
2a1/4(a+2)
But I don't get how to get that^.

Calculus 
Lindsay
an (2a4)=2(a2) or 2(2a) which will cancel out your 2a,
then do the same for the 2a+4, and this should give you your answer 
Calculus 
Untamed
Thanks so much =)

Calculus 
Reiny
I read that as
(4a^21)/(4a^216) * (2a)/(2a1) , my brackets are necessary
= (2a+1)(2a1)/( 4(a+2)(a2) * (2a)/(2a1)
the (2a)/(a2) are opposite, they will give you the 1
so..
= (2a+1)/(4(a+2)) , again you have to use brackets to write it on here. 
Calculus 
Untamed
Thanks Reiny =) But I to get everything clear, the 2a and the a2 cancel right? After I cancel those I am left with (2a+1) as the numerator:S Sorry I am just confused. Also did you factor out the 2a+4 and 2a4 to get 4(a+2)(a2)? Could you please explain step by step?
Respond to this Question
Similar Questions

Algebra
Solve Q= (NS)/ N for N So when I multiply both sides by N I get Q(N)= NS I know I am doing something wrong, the answer is in the book which is N=S/(1Q)but I don't understand were the 1 comes from. Could you write it out step by … 
algebra2
solve the equation: First: x + 3y = 5 Second: 3x  y = 5 should i use substitution or add them? 
Phys... vectors
Consider the following three vectors: a = 3i + 4j ; b = pi + 2j ; c = mi + nj , where m, n and p are constants. If: a + b = 9i + 6j a.c = 10 b x c = 2k Show that p = 6, and determine values for m and n. i got the p=6 as for the … 
Calculus
Simplify. State the nonpermissible values. (3t^2+3t6/2t^22t4)(4t^2+4t24/3t^2+6t9) This is the way I tried solving this: 3t(t1)6(t1)/2t(t1)4(t1)*4t(t2)12(t2)/3t(t+1)9(t1) (3)(t)(t1)(2)(3)(t1)/(2)(t)(t1)(2)(2)(t1)*(2)(2)(t)(t2)(2)(2)(3)(t2)/(3)(t)(t1)(3)(3)(t1) … 
Algebra II
Right now we're doing systems of Linear Equations in Three Variables. It says to solve the following system: x  y + 3z = 4 x + 2y  z = 3 4x + 3y + 2z = 5 Whatever I try with this problem (and the others like it) it comes out wrong. … 
Math
Simlifying Rational Expressions Reduce to lowest terms, stating the restrictions on the variable. I really don't understand the whole cancelling out the factor thing, and not cancelling out the terms. As I was having lots of trouble … 
mathcalculus
(5y)/(6y^27y3)+(4y3)/(2y^215y+18)consider nonpermissible values for the addition of this equation, the product of the nonpermissible values is. 5y/(2y3)(3y+1)+(4y3)(2y3)(y6) i not get what it asking for. 
GeometrySolve for x
ok so I have to solve for x in this problem. and I have tried and tried to figure it out but I cant. 12(4x2)=9(3x+2) I distributed them but after that when I try to simplify im lost. can someone please help? 
check my work on derivatives
Can someone check my work? So, I took the derivative of (1x^2)/((1+x^2)^2) I used the quotient rule ((2x((1+x^2)^2)2((1+x^2)^2)(2x)(1x^2))) / ((1+x^2)^4) Then I simplified it (2x+2x^2  4x((1+x^2)^2)(1x^2)) /((1+x^2)^4) Then I 
Math
P(n,3)=5! Solve for n?? Help, please! I did n!/(n3)!=5! n(n1)(n2)(n3)!/(n3)!=5! cancelled out (n3)! was left with n(n1)(n2)=5! n^2n(n2)=5! n^3n^2=5! n^3n^2120 What do i do?