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Simplify. State the nonpermissible values.


This is what I did to try and solve it out:


I cancelled out the (2a-1)'s and don't get how to solve.

I'm supposed to get the answer :


But I don't get how to get that^.

  • Calculus -

    an (2a-4)=2(a-2) or -2(2-a) which will cancel out your 2-a,
    then do the same for the 2a+4, and this should give you your answer

  • Calculus -

    Thanks so much =)

  • Calculus -

    I read that as
    (4a^2-1)/(4a^2-16) * (2-a)/(2a-1) , my brackets are necessary
    = (2a+1)(2a-1)/( 4(a+2)(a-2) * (2-a)/(2a-1)
    the (2-a)/(a-2) are opposite, they will give you the -1
    = -(2a+1)/(4(a+2)) , again you have to use brackets to write it on here.

  • Calculus -

    Thanks Reiny =) But I to get everything clear, the 2-a and the a-2 cancel right? After I cancel those I am left with (2a+1) as the numerator:S Sorry I am just confused. Also did you factor out the 2a+4 and 2a-4 to get 4(a+2)(a-2)? Could you please explain step by step?

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