# Calculus

posted by .

Simplify. State the nonpermissible values.

4a^2-1/4a^2-16*2-a/2a-1

This is what I did to try and solve it out:

(2a+1)(2a-1)/(2a+4)(2a-4)*2-a/(2a-1)

I cancelled out the (2a-1)'s and don't get how to solve.

I'm supposed to get the answer :

-2a-1/4(a+2)

But I don't get how to get that^.

• Calculus -

an (2a-4)=2(a-2) or -2(2-a) which will cancel out your 2-a,
then do the same for the 2a+4, and this should give you your answer

• Calculus -

Thanks so much =)

• Calculus -

I read that as
(4a^2-1)/(4a^2-16) * (2-a)/(2a-1) , my brackets are necessary
= (2a+1)(2a-1)/( 4(a+2)(a-2) * (2-a)/(2a-1)
the (2-a)/(a-2) are opposite, they will give you the -1
so..
= -(2a+1)/(4(a+2)) , again you have to use brackets to write it on here.

• Calculus -

Thanks Reiny =) But I to get everything clear, the 2-a and the a-2 cancel right? After I cancel those I am left with (2a+1) as the numerator:S Sorry I am just confused. Also did you factor out the 2a+4 and 2a-4 to get 4(a+2)(a-2)? Could you please explain step by step?

## Respond to this Question

 First Name School Subject Your Answer

## Similar Questions

1. ### Algebra

Solve Q= (N-S)/ N for N So when I multiply both sides by N I get Q(N)= N-S I know I am doing something wrong, the answer is in the book which is N=S/(1-Q)but I don't understand were the 1 comes from. Could you write it out step by …
2. ### algebra2

solve the equation: First: x + 3y = 5 Second: 3x - y = 5 should i use substitution or add them?
3. ### Phys... vectors

Consider the following three vectors: a = 3i + 4j ; b = pi + 2j ; c = mi + nj , where m, n and p are constants. If:  a + b = 9i + 6j  a.c = 10  b x c = 2k Show that p = 6, and determine values for m and n. i got the p=6 as for the …
4. ### Calculus

Simplify. State the nonpermissible values. (3t^2+3t-6/2t^2-2t-4)(4t^2+4t-24/3t^2+6t-9) This is the way I tried solving this: 3t(t-1)6(t-1)/2t(t-1)4(t-1)*4t(t-2)12(t-2)/3t(t+1)9(t-1) (3)(t)(t-1)(2)(3)(t-1)/(2)(t)(t-1)(2)(2)(t-1)*(2)(2)(t)(t-2)(2)(2)(3)(t-2)/(3)(t)(t-1)(3)(3)(t-1) …
5. ### Algebra II

Right now we're doing systems of Linear Equations in Three Variables. It says to solve the following system: x - y + 3z = 4 x + 2y - z = -3 4x + 3y + 2z = -5 Whatever I try with this problem (and the others like it) it comes out wrong. …
6. ### Math

Simlifying Rational Expressions Reduce to lowest terms, stating the restrictions on the variable. I really don't understand the whole cancelling out the factor thing, and not cancelling out the terms. As I was having lots of trouble …
7. ### math-calculus

(5y)/(6y^2-7y-3)+(4y-3)/(2y^2-15y+18)consider nonpermissible values for the addition of this equation, the product of the nonpermissible values is. 5y/(2y-3)(3y+1)+(4y-3)(2y-3)(y-6) i not get what it asking for.
8. ### Geometry-Solve for x

ok so I have to solve for x in this problem. and I have tried and tried to figure it out but I cant. 12(4x-2)=9(3x+2) I distributed them but after that when I try to simplify im lost. can someone please help?
9. ### check my work on derivatives

Can someone check my work? So, I took the derivative of (1-x^2)/((1+x^2)^2) I used the quotient rule ((2x((1+x^2)^2)-2((1+x^2)^2)(2x)(1-x^2))) / ((1+x^2)^4) Then I simplified it (2x+2x^2 - 4x((1+x^2)^2)(1-x^2)) /((1+x^2)^4) Then I
10. ### Math

P(n,3)=5! Solve for n?? Help, please! I did n!/(n-3)!=5! n(n-1)(n-2)(n-3)!/(n-3)!=5! cancelled out (n-3)! was left with n(n-1)(n-2)=5! n^2-n(n-2)=5! n^3-n^2=5! n^3-n^2-120 What do i do?

More Similar Questions