# AP Calculus

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At what value of h is the rate of increase of √h twice the rate of increase of h?

(a) 1/16
(b) 1/4
(c) 1
(d) 2
(e) 4

• AP Calculus -

let y = h
dy/dh = 1

let y = √h = h^(1/2)
dy/dh = (1/2)h^(-1/2 = 1/(2√h)

so when is 1 = 2(1/2)/(2√h)

1 = 1/(2√h)
2√h = 1
√h=1/2
h = 1/4

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