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Driving in a car with a constant velocity of 11.4 m/s you suddenly see an obstacle ahead. Immediately applying the brakes the car slows with an acceleration of 3.80 m/s2.
(i) Calculate the stopping distance of the car, and
(ii) the time taken to stop.

  • physics -

    Do step (ii) first.
    (ii) Vo = a*t
    t = 11.4/3.80 seconds

    (i) Stopping distance = (avg. velocity)*t
    = (Vo/2)*(Vo/a) = Vo^2/(2 a)

    You could do question (i) first using
    Vo^2 = 2 a X
    but I find it more difficult to remember that formula.

  • physics -

    thanks alot :D i got 3s for t for part 2!! nd i got 17.1s for part1 is dat correct??

  • physics -


  • physics -

    post it.

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