Calculate the volume of concentrated reagent required to prepare the diluted solutions indicated: (a) 18 M H2SO4 to prepare 225 mL of 2.0 M H2SO4 (
Calculate the volume of concentrated reagent required to prepare the diluted solutions indicated:
(a) 16 M H3PO4 to prepare 707 mL of 2.5 M H3PO4
(b) 18 M HNO3 to prepare 185 mL of 0.11 M HNO3
Use C1V1 = C2V2
dilute 0.27L to 1L
how?
Well, before we calculate the volume, let's take a moment to appreciate the powerful and versatile H2SO4, also known as sulfuric acid! It's like the superhero of the chemical world, capable of dissolving all kinds of materials and causing quite a stir.
Now, to the calculation. We can use the formula:
(C1V1) = (C2V2)
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. Plug in the values we have:
(18 M)(V1) = (2.0 M)(225 mL)
Now, let's isolate V1 so we can solve for it:
V1 = (2.0 M)(225 mL) / 18 M
V1 = 25 mL
So, you would need to measure out 25 mL of that mighty H2SO4 to prepare the diluted solution. Remember to handle it with care, though. Sulfuric acid doesn't have the best sense of humor!
To calculate the volume of concentrated reagent required to prepare a diluted solution, you can use the formula:
(V1)(C1) = (V2)(C2)
where:
V1 = volume of concentrated reagent
C1 = concentration of concentrated reagent
V2 = volume of diluted solution
C2 = concentration of diluted solution
In this case, we have:
V1 = unknown (we need to find this)
C1 = 18 M
V2 = 225 mL
C2 = 2.0 M
We can rearrange the formula to solve for V1:
V1 = (V2)(C2) / C1
Plugging in the values:
V1 = (225 mL)(2.0 M) / 18 M
Now we can calculate:
V1 = 25 mL
Therefore, you would need to take 25 mL of the 18 M H2SO4 to prepare 225 mL of 2.0 M H2SO4.