precalulus
posted by Anon .
Ok feeling kinda dumb because this isn't coming out right. I know it's simple.
log6 (x 3) + log6(x 6)  log6(x + 1) = 2

adding logs is multiplying arguments
log 6 [(x3)(x6)(x+1)] = 2
6^log 6 [(x3)(x6)(x+1)] = 6^2 = 36
x^3  8 x^2 + 9 x + 18 = 36
x^3  8 x^2 + 9 x  18 = 0
I do not see any easy factors. Have to solve by iteration.