Tim needs batteries.AA batteries cost $3 per pack.D batteries cost $4 per pack. If she has $26 to spend and buys 3 times as many packs of AA batteries as D, how many packs of each does she buy?
4x+3(3x)=26
4x+9x=26
13x=26
x=2
4(2)+9(2)=26
8+18=26
26=26
8/4=2 D batteries
18/3=6 AA batteries
I really don't know. I have this problem on my homework and was sooooo confused.
To solve this problem, we can set up equations based on the given information. Let's assume Tim buys x packs of D batteries. According to the problem, she buys 3 times as many packs of AA batteries as D. Therefore, she buys 3x packs of AA batteries.
The cost of each pack of AA batteries is $3, so the total cost of AA batteries will be 3x * $3 = $9x.
Similarly, the cost of each pack of D batteries is $4, so the total cost of D batteries will be x * $4 = $4x.
Since Tim has $26 to spend, the total cost of the batteries should equal $26. So, we can form the following equation:
$9x + $4x = $26
Combining like terms, we simplify the equation to:
$13x = $26
To isolate x, the variable representing the number of packs of D batteries, we divide both sides of the equation by $13:
x = $26 / $13
x = 2
Therefore, Tim buys 2 packs of D batteries. Since she buys 3 times as many packs of AA batteries, she buys 3 * 2 = 6 packs of AA batteries.
In summary, Tim buys 2 packs of D batteries and 6 packs of AA batteries.