math/ calculus

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full work out with explanation of this problem please we're working with derivatives and i don't understand it

given h(x)= cotx/x find h'(pi/2)

  • math/ calculus -

    h = f/g so
    h' = (f'g - fg')/g^2

    h'(x) = [-x csc^2(x) + cot(x)]/x^2

    h'(pi/2) = [-pi/2 * 1 + 0]/(pi^2 / 4)
    = - 2/pi

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