Physics

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a ball is released from rest and rolls down in an inclined plane, requiring 4 sec. to cover a certain distance of 100m. a) what is the acceleration?
b) how many cm would it have fallen vertically in the same time?

  • Physics -

    We will be glad to critique your thinking, but don't have time to do all your work for you. The average speed (25 m/s in this case) tells you that the final velocity 50 m/s. Divide that by the elapsed time for the aceleration.

    I am sure you know the formula for the time to fall Y vertically.
    Y = (1/2)g t^2
    Use it. You may have to convert meters to cm.

  • Physics -

    fbzffb

  • Physics -

    a) a=2(distance)/time^2
    = 2(100cm)/16s^2
    =12.5 cm/s^2

    b) s= (gt^2)/2
    since g = 9.8 m/s^2
    = (9.8 x 16)/2
    =78.4 m
    or 7840 cm

  • Physics -

    a) a=2(distance)/time^2
    = 2(100cm)/16s^2
    =12.5 cm/s^2

    b) s= (gt^2)/2
    since g = 9.8 m/s^2
    = (9.8 x 16)/2
    =78.4 m
    or 7840 cm

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