Calculus

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6x-4cos(3X)Critical Numbers

  • Calculus -

    There is no function here. Is there an equal sign somewhere here? A function? What is your question?

  • Calculus -

    presumably you meant

    y = 6x - 4cos(3x)
    y' = 6 + 12sin(3x)
    y'' = 36cos(3x)

    Now, I'm sure you know all about 1st and second derivatives and how they relate to critical numbers:

    y has a max/min where y' = 0 and y'' not zero
    y has an inflection point where y'' = 0
    y is increasing where y' >. 0
    y is concave up when y'' > 0

    No go plug and chug

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