pre calculus
posted by James
Write the expression below as a single logarithm. Need to know how to work this!
ln(x5/x^2  1)  ln (x^2  2x 15/x + 1)

Reiny
ln(x5/x^2  1)  ln (x^2  2x 15/x + 1)
= ln(x5)  ln(x^2  1)  (ln(x5)(x+3)  ln(x+1) )
= ln(x5) ( (ln (x+1) + ln(x1) )  ( ln(x5) + ln(x+3)  ln(x+1) )
= ln(x5)  ln(x+1)  ln(x1)  ln(x5)  ln(x+3) + ln(x+1)
= ( ln(x1) + ln(x+3) )
= ln( (x1)(x+3) )
or ln(x^2 + 2x  3) 
James
Thank you!
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