math
posted by latesha .
One number is eight more than twice another. If their sum is decreased by nine, the result is fourteen. Find the numbers.

n = (8 + 2 m)
n + m  9 = 14

(8 + 2 m) + m = 23
8 + 3 m = 23
3 m = 15
m = 5
n = 18