Pre-Calc-Please check answer

posted by .

1.Write 4+6+8+10 in sigma notation:
I came up with sigma in the middle
3 on top
j=0 on the bottom
2n+4 to the right of the signma sign

2. Find the 10th term of the sequence
-1/5,-1/20,-1/80 this was a geometric sequence so I said a(subscript10) = -1/5*1/4^(10-1)
=-1/5*(1/4)^9 = -1/5*1/2621444
= -1/1310702

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. algebra

    I'm pretty sure these are right but I just want to check. 1)Find the 20th term of the arithmetic sequence in which a1=3 and d=7 a.143 b.136 c.140 d.133 answer=b 2)Write an equation for the nth term of the arithmetic sequence -3,3,9,15... …
  2. algebra(check)

    I'm pretty sure these are right but I just want to check. 1)Find the 20th term of the arithmetic sequence in which a1=3 and d=7 a.143 b.136 c.140 d.133 answer=b 2)Write an equation for the nth term of the arithmetic sequence -3,3,9,15... …
  3. algebra

    I'm pretty sure these are right but I just want to check. 1)Find the 20th term of the arithmetic sequence in which a1=3 and d=7 a.143 b.136 c.140 d.133 answer=b 2)Write an equation for the nth term of the arithmetic sequence -3,3,9,15... …
  4. algebra

    I'm pretty sure these are right but I just want to check. 1)Find the 20th term of the arithmetic sequence in which a1=3 and d=7 a.143 b.136 c.140 d.133 answer=b 2)Write an equation for the nth term of the arithmetic sequence -3,3,9,15... …
  5. Algebra

    find the indicated sum not sure how to type the sigma sign, but here is the problem 6 on top of the sigma sign. under the sigma sign is i=3 and on the right side of the sigma sign (3i-2)
  6. Algebra II

    Please help-I need to write 4+6+8+10 in sigma notation would it be sigma sign in middle (3) on top of sign, n=0 on bottom of signma notation and to the right it would be (4+2n) so it would look like-- (3) (sigma in middle) (4+2n) n=0
  7. Pre-Calc-Please check

    1.Write 4+6+8+10 in sigma notation: I came up with sigma in the middle 3 on top j=0 on the bottom 2. Find the 10th term of the sequence -1/5,-1/20,-1/80 this was a geometric sequence so I said a(subscript10) = -1/5*1/4^(10-1) =-1/5*(1/4)^9 …
  8. Pre-Calc-Please check answer

    1.Write 4+6+8+10 in sigma notation: I came up with sigma in the middle 3 on top j=0 on the bottom 2n+4 to the right of the signma sign 2. Find the 10th term of the sequence -1/5,-1/20,-1/80 this was a geometric sequence so I said a(subscript10) …
  9. Pre-CalcPlease check

    Please check: 1.Write in expanded form: this is a sigma notation- 4 on top signma in middle k=1 on bottom to right of sigma is (k-1)(k-2) I solved: k=1 (1-1)(1-2)=0(-1)=0 K=2 (2-1)(2-2) = 1(0)=0 k=3(3-1)(3-2)=2(1)=2 k=4 (4-1)(4-)=3(2)=6 …
  10. Pre-Calc-please check

    Please check this for me expand (3z-2b)^5 using Binomial Theorem (a+b)^n = n on top sigma in middle k=0 to right (n/k)a^(n-k)b^k (3a-2b)^5 = 5 on top sigma in middle k=0 on bottom(5/k)(3a)^5-k(-2b)^k (5/0)(3a)^5(-2b)^0+(5/1)(3a)^4(-2b)^1 …

More Similar Questions