mrs. cooper's class has 11 more girls than boys. there are 35 students in all. how many girls are there?
Sum and difference problems can be readily solved without algebra by the following:
bigger number = (sum+difference)/2
smaller number = (sum - difference)/2
Example, since there are more girls than boys, so
number of girls = (35+11)/2 = 23
number of boys = (35-11)/2 = 12
mrs cooper has 35 students in her class. she has 11 more girls than boys. How many girls are in her class.
24 girls
To find out how many girls there are in Mrs. Cooper's class, we can first set up a system of equations based on the information given.
Let's assume the number of boys in the class as 'b' and the number of girls as 'g'.
According to the information given, we can create two equations:
Equation 1: "Mrs. Cooper's class has 11 more girls than boys."
g = b + 11
Equation 2: "There are 35 students in all."
g + b = 35
Now we have a system of equations:
g = b + 11 (Equation 1)
g + b = 35 (Equation 2)
To solve this system, we can substitute Equation 1 into Equation 2.
(b + 11) + b = 35
Simplifying this equation, we get:
2b + 11 = 35
Subtract 11 from both sides:
2b = 35 - 11
2b = 24
Divide both sides by 2 to solve for b:
b = 24 / 2
b = 12
Now that we know the number of boys is 12, we can substitute this value back into Equation 1 to find the number of girls:
g = 12 + 11
g = 23
Therefore, there are 23 girls in Mrs. Cooper's class.