Calculate the approximate volume of a 0.600 mol sample of gas at 15.0 degrees C and a pressure of 1.10 atm.
To calculate the volume of a gas, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
Given:
n = 0.600 mol
P = 1.10 atm
T = 15.0 degrees C
To convert the temperature to Kelvin, we need to add 273.15.
T = 15.0 + 273.15 = 288.15 K
Now we can rearrange the ideal gas law equation to solve for the volume:
V = (nRT) / P
Plugging in the values:
V = (0.600 mol * 0.0821 L·atm/(mol·K) * 288.15 K) / 1.10 atm
Let's calculate this step by step:
Step 1: Multiply n, R, and T
nRT = (0.600 mol * 0.0821 L·atm/(mol·K) * 288.15 K) ≈ 14.9741 L·atm
Step 2: Divide nRT by P
V = (14.9741 L·atm) / 1.10 atm ≈ 13.6137 L
Therefore, the approximate volume of the gas sample is 13.6 L.
To calculate the approximate volume of a gas sample, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
First, let's convert the given temperature from Celsius to Kelvin. To do this, we add 273.15 to the Celsius value:
T = 15.0 + 273.15 = 288.15 K
Now, rearrange the ideal gas law equation to solve for V, the volume:
V = (nRT) / P
Substituting the given values:
V = (0.600 mol * 0.0821 L·atm/(mol·K) * 288.15 K) / 1.10 atm
Calculating this expression will give you the approximate volume of the gas sample in liters.
PV=nRT
Solve for V.
Here's a sample problem:
http://faculty.clintoncc.suny.edu/faculty/Mike.Lawliss/My_webpage/map/pvnrt.htm