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College Algebra

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A rectangle field with area of 1,500,000 needs to be fenced. 2W+2L=5,000. solve for L and W

  • College Algebra -

    so you would have
    WL = 1500000
    and W+L = 2500
    or L = 2500-W

    back into the 1st...
    W(2500-W) = 1500000
    -w^2 + 2500W - 1500000 = 0
    w^2 - 2500W + 1500000=0
    (W-1500)(W - 1000) = 0
    W = 1500 or W = 1000

    If W = 1500, then L = 1000
    I W = 1000 , then L = 1500

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