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When 30.0 grams of aluminum reacts with HCl how many grams of aluminum chloride are formed? Al = HCl yields AlCl3 + H 2

  • Chem -

    the mol wt of Al is 27

    30g of Al = 1.11 mol

    so, we end up with 1.11 mol of AlCl3

    that would be 1.11(27 + 3*35.45) = 148g

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