posted by Tengo anos Cuarenta y uno
Given: line AB is congruent to line AC, Angle BAD is congruent to angle CAD.
Prove: line AD bisects BC
Picture: An upside down triangle divided inhalf to form two triangles Angle BAD and angle CAD. They share a common side of AD. and point D bisects line BC. and Angle c and Angle B are corresponding and congruent.
what i have so far
Line DA is congruent to Line DA by Reflexive Prop or EQuality
angle C is congruent to angle B by the Corresponding parts of congruent triangles are congruen. CPCTC.
but i do not know where to go from that..
As far as I can tell, it doesn't matter which lines are congruent.
<BAD and <CAD are adjacent angles which are equal.
Therefore they bisect <CAB
Gussy it up, but that's the crux of the argument.
how to place information to get answer of geometric mean of 25.4, 9, 16, 4.25, 8.11, 19?
You know it's almost 2017 already.
You'd think that you'd get an actual answer from Tengo anos Cuarenta y uno or at least someone would answer Tengo anos Cuarenta y uno right.