Trig
posted by Lenny .
The set of solution(s) of 2 cos^2
(θ)  13 cos(θ) + 6 = 0 that is(are) in the
interval (0,π/2) is one of following
a. {π/6} b. {π/3}
c. {π/4}
d. {π/3, π/6}
e. {π/6, π/4}

This is just a quadratic in cosθ
2cos^2θ  13cosθ + 6 = 0
(2cosθ  1)(cosθ  6) = 0
so,
2cosθ = 1
cosθ = 1/2
θ = π/3
or,
cosθ = 6
no solutions there
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