math
posted by michael .
a ladder leaning against a wall makes a 60 degree angle with the ground. the base of the ladder is 4m from the building. how high above the ground is the top of the ladder?

tan 60° = height/4
height = 4tan60 = ..... 
problem im on online schooling and its a special right triangles assignment and i don't have a calculator do to tangent and all that so that's why i need help.

You should really get yourself a scientific calculator.
You can now get them around $10, I have seen them sell at about $5
Secondly you should memorize the ratio of sides of the standard 30690 and the 454590 rightangled triangles, in this case this is what they probably expected
the sides opposite the 306090 are 1 , √3, 2
and for the 454590 the sides are 1, 1, √2
so tan 60 = √3/1
=1.7321
so height = 4(1.7321) = 6.93 appr 
short leg = 4; to find long leg multiply 4 x 2; long leg = 8; to find how high; use x^2 + 4^2 = 8^2
so: x^2 + 16 = 64; subtract 16 from both sides: x^2 = 48; find the square root of 48; x = 6.93 so the top of the ladder is 6.93 m above the ground.