posted by michael .
a ladder leaning against a wall makes a 60 degree angle with the ground. the base of the ladder is 4m from the building. how high above the ground is the top of the ladder?
tan 60° = height/4
height = 4tan60 = .....
problem im on online schooling and its a special right triangles assignment and i don't have a calculator do to tangent and all that so that's why i need help.
You should really get yourself a scientific calculator.
You can now get them around $10, I have seen them sell at about $5
Secondly you should memorize the ratio of sides of the standard 30-6-90 and the 45-45-90 right-angled triangles, in this case this is what they probably expected
the sides opposite the 30-60-90 are 1 , √3, 2
and for the 45-45-90 the sides are 1, 1, √2
so tan 60 = √3/1
so height = 4(1.7321) = 6.93 appr
short leg = 4; to find long leg multiply 4 x 2; long leg = 8; to find how high; use x^2 + 4^2 = 8^2
so: x^2 + 16 = 64; subtract 16 from both sides: x^2 = 48; find the square root of 48; x = 6.93 so the top of the ladder is 6.93 m above the ground.