A rock band playing an outdoor concert produces sound at 120 5.0 away from their single working loudspeaker.

and....

To find the answer to this question, we need to understand how sound intensity decreases with distance. Sound intensity follows an inverse square law, which means that as you move away from the source, the intensity of the sound decreases proportionally to the square of the distance.

In this case, the rock band is playing at a distance of 120 meters away from the loudspeaker. We need to determine how the sound intensity changes over this distance.

According to the inverse square law, the sound intensity will be inversely proportional to the square of the distance. Mathematically, this can be represented as:

I2 = I1 / (r2/r1)^2

Where:
I1 = initial sound intensity at a reference distance (r1)
I2 = new sound intensity at the desired distance (r2)

In this case, the initial sound intensity (I1) is unknown, and we need to find it. However, we do know the sound intensity (I2) at the desired distance (5.0 meters).

To find I1, we rearrange the equation:

I1 = I2 * (r2/r1)^2

Plugging in the values:
I1 = I2 * (5.0/120)^2

Now we can calculate the sound intensity at the loudspeaker position, which is the reference distance (r1 = 0) in this case. We know the sound intensity at the desired distance (I2) which is not provided in the question. So, unfortunately, without knowing the sound intensity at the desired distance, we cannot calculate the sound intensity at the loudspeaker position.

In summary, without additional information about the sound intensity at 5.0 meters from the loudspeaker, we cannot determine the sound intensity at the loudspeaker position.