How much heat does it take to raise 1.0 kg of lead from 0 degree celsius to 90 degree celsius?
To calculate the amount of heat required to raise the temperature of a substance, you can use the specific heat capacity formula. The specific heat capacity (c) is the amount of heat required to raise the temperature of one kilogram of a substance by one degree Celsius.
The specific heat capacity of lead is 0.13 J/g°C, or 130 J/kg°C.
To calculate the heat required, we need to consider the change in temperature (ΔT), which is the final temperature minus the initial temperature.
ΔT = 90°C - 0°C = 90°C
Now we can use the formula:
Q = mcΔT
Where:
Q is the amount of heat required (in joules),
m is the mass of the substance (in kilograms),
c is the specific heat capacity (in J/kg°C),
and ΔT is the change in temperature (in degrees Celsius).
Plugging in the values:
Q = (1.0 kg) × (130 J/kg°C) × (90°C)
Q = 11,700 J
Therefore, it takes 11,700 joules (J) of heat to raise the temperature of 1.0 kg of lead from 0°C to 90°C.