How much heat does it take to raise 1.0 kg of lead from 0 degree celsius to 90 degree celsius?
heat= mass*specificheat*changinTemp
so 1*90*90?
To calculate the heat required to raise the temperature of a substance, you need to use its specific heat capacity (C).
First, let's find the specific heat capacity of lead. The specific heat capacity is the amount of heat required to raise the temperature of one kilogram of a substance by one degree Celsius. For lead, it is approximately 0.13 J/g°C (joules per gram per degree Celsius).
To convert this value to joules per kilogram per degree Celsius, we need to multiply by 1000 (since there are 1000 grams in one kilogram):
0.13 J/g°C * 1000 g/kg = 130 J/kg°C
Now that we have the specific heat capacity for lead (C = 130 J/kg°C), we can calculate the heat required using the formula:
Q = m * C * ΔT
where Q is the heat required, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature.
In this case, the mass of lead (m) is 1.0 kg, the specific heat capacity (C) is 130 J/kg°C, and the change in temperature (ΔT) is 90°C (since we're going from 0°C to 90°C).
Plugging in these values into the formula:
Q = 1.0 kg * 130 J/kg°C * 90°C
Q = 11,700 J (joules)
Therefore, it would take 11,700 joules of heat to raise 1.0 kg of lead from 0°C to 90°C.