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Calculate the amount of moles in CH3COOH which is 5%acedic acid and C3H7OH which is 70% usp? This is what I got.....For the amount of 50 ml -> 50mL = 50g ->50g/18.016 = 2.7 moles in 50 ml of H2O
For the amount of 50 ml -> 50mL = 50g ->50g/60.09500 g = .83 moles in 50 ml


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    What's the question? Is the 5% CH3COOH and 70% usp propanol two different problems or somehow intertwined into the same problem? And what does 50 mL have to do with it?

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