which conversion factor do you use to first calculate the number of grams of CO2 produced by tge reaction of 50.6 CH with O2? The equation for the complete combustion of methane is:
CH4 (g) + 2o2 (g) ---> CO2 (g) +2H2o (l)
a. 2 mol O2/1 mol CO2
b. 1 mol CH4/16.0g of CH4
c. 44.0 g CO2/2 mol CO2
d. 16.0 CH4/1 mol CO4
please help!!
To determine the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with O2, we need to use the appropriate conversion factor.
We can start by converting the given mass of CH4 to moles using the molar mass of CH4.
The molar mass of CH4 is: 1 C + 4 H = 12.01 g/mol + 4(1.01 g/mol) = 16.04 g/mol
The conversion factor we use is:
1 mol CH4 / 16.04 g CH4
Thus, the correct conversion factor is option b. 1 mol CH4/16.0 g of CH4.
To calculate the number of grams of CO2 produced by the reaction, you need to use the conversion factor that relates the amount of methane (CH4) to the amount of carbon dioxide (CO2) produced.
The balanced equation for the complete combustion of methane tells us that 1 mole of CH4 reacts to produce 1 mole of CO2. Therefore, the conversion factor you need to use is:
1 mol CH4 / 1 mol CO2
Looking at the given options:
a. 2 mol O2 / 1 mol CO2: This is not the correct conversion factor as it relates the amount of oxygen (O2) to carbon dioxide (CO2), not methane (CH4) to carbon dioxide (CO2).
b. 1 mol CH4 / 16.0 g of CH4: This is not the correct conversion factor as it relates the amount of methane (CH4) to its mass. We need to convert moles of CH4 to moles of CO2.
c. 44.0 g CO2 / 2 mol CO2: This is the correct conversion factor as it relates the amount of carbon dioxide (CO2) to its mass in grams (44.0 g) and the number of moles (2 mol).
d. 16.0 CH4 / 1 mol CO4: This is not the correct conversion factor as it relates the amount of methane (CH4) to a non-existent compound CO4.
Therefore, the correct conversion factor to use is:
c. 44.0 g CO2 / 2 mol CO2
By multiplying the given amount of CH4 (50.6 g) by this conversion factor, you will be able to calculate the number of grams of CO2 produced by the reaction.
You omitted the units for 50.6 (WHAT--grams?) and CHWHAT? CH4?
First you want to convert 50.6 g CH4 to moles.
50.6 x (1 mole CH4/16 g CH4) = ?