# Precalculus

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Whats the value of a? =-=

For the graph, determine the equation of the function in the form y=a(x-h)^2+k.

Then describe the transformations that were applied to y=x^2 to obtain the graph.

Here is the graph: imgur dot com/A7e5M

The only thing I know is that:

1. Reflected in x-axis
2. vertical shift UP 2

Whats the vertical compression/stretch? halps~

• Precalculus -

This time I was able to see your graph,
the new vertex is (0,2) and another point on it is (1,-1)

so if the parent equation is y = x^2
the new equation is
y = a(x-0)^2 + 2
y = ax^2 + 2
but the point (1,-1) lies on it
1 = a(-1)^2 + 2
1 = a + 2
a = -1

new equation: y = -x^2 + 2

Notice that because of the position of the new point (1,-1) the value of a turned out be negative, which we expected, since it opens downwards

• Precalculus -

Thank you Reiny!!!!!!!

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