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Simlifying Rational Expressions

Reduce to lowest terms, stating the restrictions on the variable. I really don't understand the whole cancelling out the factor thing, and not cancelling out the terms. As I was having lots of trouble with this stuff this is the way I was told do solve an equation.

a cannot equal 0.

^ But even following it that way I still sort of get confused.

These are the ones I really need help on. And could you please just teach me the rules and stuff for Simplifying rational expressions and stating the restrictions. If you could show me a bunch of examples that would be great, thanks.

Questions - -"Stuck" on.



*Tried solving this one...

I cancelled out the (b-9)'s and I cancelled out the b's( the one beside 2 and the one in the denominator, I wasn't sure whether they are considered as terms and if they should not be cancelled out, but it never made sense to not cancel them out so I did)

And I was left over with : 2/b-9

And the restriction part:
*Imagine the equal sign as a nonequal one

b-9 = 0
Added 9 to both sides
b = 9
Meaning b cannot equal nine. Is that the only restriction? Cause that's the only one I solved.

* t^2+4t+4/2t^2+10t+12



^ And I'm stuck :\

  • Math -

    Questions - -"Stuck" on.

    = a^2/(a(a+1))
    = a/(a+1) , a≠ 0

    2-3/r-2 ????? , did you mean (2-r)/(r-2) ?
    if so, then ...
    = -1(r-2)/(r-2)
    = -1 , r≠2

    I will assume you meant: (2b^2-18b)/( b(b-9)^2 )
    = 2b(b-9)/((b-9)(b-9) )
    = 2b/(b-9) , b ≠ 9

    t^2+4t+4/2t^2+10t+12 , I will again assume you meant (t^2+4t+4)/(2t^2+10t+12)
    = (t+2)(t+2)/(2 (t+2)(t+3) )
    = (t+2)/(2t+6) , t ≠-3

    In the last, it looks like you were factoring by decomposition.
    I will do the bottom:
    2t^2 + 10t + 12
    = 2t^2 + 6t + 4t + 12
    = 2t(t+3) + 4(2t+3) , you had these as being multiplied rather than added
    = (t+3)(2t+4)
    = (t+3)(2)(t+2)
    = 2(t+3)(t+2)

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