Using the codon table, determine the sequence of the protein that will be produced from the

mRNA sequence below. Be sure to begin with a start codon.
5'-CCCAAUGUUGCGGCCAUGACAC-3'

A. N-Methionine-Leucine-Arginine-Proline-C
B. N-Methionine-Histidine-Serine-Threonine-Glycine-Valine-Valine-Threonine-C
C. N-Histidine-Serine-Threonine-Glycine-Valine-Valine-Threonine-C
D. N-Methionine-Proline-Aspartate-Valine-Alanine-Alanine-Methionine-Threonine-C
E. N-Proline-Aspartate-Valine-Alanine-Alanine-Methionine-Threonine-C

The answer is supposed to be A) but I have no idea why. Please help, I have tried looking on the internet and I still don't understand how the answer for this is A.

Do you understand how to use the codon table?

Break the sequence into groups of three first. Then, find out what each group of three equals using the codon table.

It is (A) because after "CCCAA" you can see "AUG "UUG" "CGG" CCA", the codes for methionine, leucine, arginine, and proline.

None of the other answers are in the right sequence.

To determine the sequence of the protein, we need to translate the mRNA sequence into its corresponding amino acids using the codon table. Let's break down the process step by step:

1. Start codon: The mRNA sequence begins with 5'-CCCAAUGUUGCGGCCAUGACAC-3'. The start codon in the genetic code is "AUG," which codes for the amino acid Methionine (Met). This gives us the first amino acid: N-Methionine.

2. Reading triplets (codons): From the start codon "AUG," we move on to the next triplet or codon. Let's break down the sequence into codons:
- CCC: This codon codes for Proline (Pro).
- AAU: This codon codes for Asparagine (Asn).
- GUU: This codon codes for Valine (Val).
- GCG: This codon codes for Alanine (Ala).
- CCA: This codon codes for Proline (Pro).
- AUG: This codon codes for Methionine (Met).

3. Stop codon: The translation stops when a stop codon is encountered. The stop codons are UAA, UAG, and UGA. In the given mRNA sequence, we don't encounter a stop codon in the provided region. Therefore, the translation continues until the end of the sequence.

Putting it all together, the translation of the mRNA sequence 5'-CCCAAUGUUGCGGCCAUGACAC-3' would result in the protein sequence N-Methionine-Leucine-Arginine-Proline-C. Therefore, the correct answer is A) N-Methionine-Leucine-Arginine-Proline-C.

It's important to note that the codon table provides the correspondence between codons and amino acids. By reading the mRNA sequence and consulting the table, you can determine the amino acids encoded by each codon.