posted by syakila .
) ∫_(-1)^2 ∫_0^6▒〖x² sin(x-y)dxdy= 〗 ∫_0^6 ∫_(-1)^2▒〖x^2 sin(x-y)dydx〗
determine whether the statement is true or false. If it is true, explain why. If it is false, explain why or give an example that disproves the statement.
It is illegible. I see backwards parentheses, unexplained shaded areas and cryptic symbols.
I suggest you make the changes
(-1)^2 = 1 and
0^6 = 1
Then it looks like you will comparing two indefinite double integrals with the order of integration reversed.
If that really is a 0^6 on both sides of your equation, that number can be replaced by zero. (NOT 1)
That would make both sides of the equation zero, and the equation valid.
I am sorry about that error, and ashamed of myself.