Compound B is provided as a solution and has a specific gravity of 0.65 (Specific gravity is the weight in grams per mL of solution) and is known to be 90% pure (each gram of compound B solution only contains 90% Compound B and 10% of degradation products). 4.5 mL of Compound B is diluted with 55.5mL of water. What is the concentration of this solution?
To find the concentration of the final solution, we need to calculate the amount of pure Compound B present in the diluted solution.
First, let's find the weight of Compound B in the original solution. The specific gravity tells us that the weight of the original solution is 0.65 grams per mL. Since we have 4.5 mL of Compound B, the weight of the original solution is:
Weight of original solution = 0.65 g/mL * 4.5 mL
Next, we need to find the weight of pure Compound B in the original solution. We know that the original solution is 90% pure Compound B, so:
Weight of pure Compound B = 90% * Weight of original solution
Now, we can calculate the weight of pure Compound B in the original solution.
To find the concentration of the final solution, we need to divide the weight of pure Compound B by the total volume.
Total volume of the final solution = volume of Compound B + volume of water
Total volume = 4.5 mL + 55.5 mL
Finally, we can calculate the concentration of the final solution:
Concentration = Weight of pure Compound B / Total volume of the final solution
Let's calculate the values step by step:
1. Weight of original solution = 0.65 g/mL * 4.5 mL
Weight of original solution = 2.925 grams
2. Weight of pure Compound B = 90% * 2.925 grams
Weight of pure Compound B = 2.6325 grams
3. Total volume = 4.5 mL + 55.5 mL
Total volume = 60 mL
4. Concentration = 2.6325 grams / 60 mL
Therefore, the concentration of the final solution is approximately 0.044 grams/mL or 44 g/L.