an average sized female spider and a large spider can lay a total of 2,100 eggs at one time.The large spider lay 20 times the number of eggs as the average sized spider.How many eggs does the average sized spider lay?
N + 20 N = 21 N = 21,000
Solve for N
To solve this problem, let's assume that the number of eggs laid by the average-sized spider is 'x'.
We are given that the large spider lays 20 times the number of eggs as the average-sized spider. So, the number of eggs laid by the large spider would be 20x.
We are also given that the total number of eggs laid by both spiders combined is 2,100. Therefore, we can set up the equation:
x + 20x = 2,100
Combining like terms, we get:
21x = 2,100
To find the value of x, we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by 21:
(21x) / 21 = 2,100 / 21
Simplifying, we have:
x = 100
So, the average-sized spider lays 100 eggs.