I am a prime number. I am less than 40. I am 1 more than a multiple of 5. What number am I?
I am a 2 digit number. My ones digit is 2. My tens digit is even. I am between 30 and 70. what number am i? I think either 42 or 62.
I am a square number. I am more than 50. My digits total 9. what number am i?
I figured these out, thanks anyway.
they are:
2
42 and 62
81 and 144
i am a 3digit number that is less than 500. My ones digit is twice the hundreds digit. The sum of the three digits is 14. What number am I?
To find the prime number that is less than 40 and 1 more than a multiple of 5, we can start by listing the multiples of 5: 5, 10, 15, 20, 25, 30, 35. However, we're looking for a number that is 1 more than a multiple of 5, so we need to add 1 to each of these multiples: 6, 11, 16, 21, 26, 31, 36.
Out of these numbers, only 11 is a prime number. Therefore, the prime number that satisfies the given conditions is 11.
For the 2-digit number with the ones digit being 2 and the tens digit being even, we can narrow down the options between 30 and 70. The possible numbers are 32, 42, 52, 62, and 72. Since the tens digit needs to be even, we can eliminate 52 and 72.
Therefore, the number that satisfies the given conditions is 42.
Lastly, to find the square number with a digit sum of 9 and is more than 50, we can start listing the square numbers greater than 50: 64, 81, 100, 121, 144, 169, 196, 225. The only number that has a digit sum of 9 is 81.
Therefore, the number that satisfies the given conditions is 81.
To find the prime number that is less than 40 and 1 more than a multiple of 5, we can start by listing the multiples of 5: 5, 10, 15, 20, 25, 30, 35, and 40. Adding 1 to each of these numbers, we get: 6, 11, 16, 21, 26, 31, 36, and 41.
From this list, we can see that the number 41 is the only prime number since it is not divisible by any other number besides 1 and itself.
For the second question, to find the two-digit number where the ones digit is 2 and the tens digit is even, we can list the even numbers between 30 and 70: 32, 42, 52, 62, and 72. Among these options, the only number that satisfies the condition of having a ones digit of 2 is 62.
Lastly, to find the square number that is more than 50 and the digits of which sum to 9, we can start by listing the squares of numbers greater than 7 (because 7^2 = 49, which is less than 50).
The squares of numbers greater than 7 are: 9, 16, 25, 36, 49, 64, 81, 100, 121, and so on. Among these options, the only numbers that have digits summing up to 9 are 81 and 9 (8 + 1 = 9, and 9 + 0 = 9, respectively). However, since we are looking for a number greater than 50, the answer is 81.