6. Compound C (MW = 550) is provided at a concentration of 25g/100mL. 1mL is taken and compound D is to be added (MW = 1025, concentration = 75mM) to give a final ratio of compound C:D of 4:1. What volume of compound D is to be added?
Do you want a ratio of 4:1 by grams or 4:1 by moles; i.e., do you want a grams ratio or mole ratio of 4:1 C:D?
moles please show me the steps on how to do it thanks
The ratio of 4:1 by moles DrBob222
To find the volume of compound D to be added, we need to calculate the volume of compound C in the 1mL sample and then determine the corresponding volume of compound D:
1. Calculate the amount of compound C in 1mL:
- Concentration of compound C = 25g/100mL
- Amount of compound C in 1mL = (25g/100mL) * 1mL = 0.25g
2. Convert the amount of compound C to moles:
- Molecular Weight of compound C (MW) = 550g/mol
- Moles of compound C in 1mL = 0.25g / 550g/mol = 0.0004545 mol
3. Determine the amount of compound D needed to achieve a 4:1 ratio with compound C:
- Given ratio of compound C:D = 4:1
- Moles of compound D in 1mL = 0.0004545 mol / 4 = 0.0001136 mol
4. Convert the moles of compound D to volume using its concentration:
- Concentration of compound D = 75mM (millimoles per liter)
- Volume of compound D = Moles of compound D / Concentration of compound D
- Volume of compound D = 0.0001136 mol / 75mM = 0.001514 mL
Therefore, in order to achieve a 4:1 ratio of compound C to compound D in the 1mL sample, you would need to add approximately 0.001514 mL of compound D.