Calculus

posted by .

Finding area under a curve

From [1,3]
2x^2 -4x +1

  • Calculus -

    is your curve y = 2x^2 - 4x + 1 ?
    Is your region between the curve and the x-axis within your stated domain ?
    Did you notice that the parabola has an x-intercept within your domain?

  • Calculus -

    its from 1 to 3 on the x axis including when it crosses underneath, you subtract that (its like negative area)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calculus

    Integrals: When we solve for area under a curve, we must consider when the curve is under the axis. We would have to split the integral using the zeros that intersect with the axis. Would this be for all integrals?
  2. calculus

    suppose that the area under the curve y=1/x from x=a to x=b is k. the area in terms of k, under the curve y=1/x from x=2a to x=2b?
  3. Calculus ll - Improper Integrals

    Find the area of the curve y = 1/(x^3) from x = 1 to x = t and evaluate it for t = 10, 100, and 1000. Then find the the total area under this curve for x ≥ 1. I'm not sure how to do the last part of question ("find the the total …
  4. Math

    Estimate the are under the curve f(x)=x^2-4x+5 on [1,3]. Darw the graph and the midpoint rectangles using 8 partitions. Show how to calculate the estimated area by finding the sum of areas of the rectangles. Find the actual area under …
  5. Math: Need Answer to study for a quizz. Help ASAP

    Estimate the area under the curve f(x)=x^2-4x+5 on [1,3]. Darw the graph and the midpoint rectangles using 8 partitions. Show how to calculate the estimated area by finding the sum of areas of the rectangles. Find the actual area under …
  6. Calculus

    what is Trapezoidal rule? How does it work in finding the area under the curve(s)?
  7. math

    i need help finding area under curve of:2y=sqrt(3x),y=4, and 2y+1x=4
  8. Calculus

    i need help finding area under curve of:2y=sqrt(3x),y=4, and 2y+1x=4
  9. Calculus

    Find the area cut off by x+y=3 from xy=2. I have proceeded as under: y=x/2. Substituting this value we get x+x/2=3 Or x+x/2-3=0 Or x^2-3x+2=0 Or (x-1)(x-2)=0, hence x=1 and x=2 are the points of intersection of the curve xy=2 and the …
  10. Stats

    Need help finding the area under the normal curve between z = -1.0 and z = -2.0?

More Similar Questions