How much heat energy is required to convert 0.1000kg of ice at -10.0 C into water at 50 C?
Add heat required for these three component steps:
(1) raising T of ice by 10 C
(2) melting the ice at 0 C
(3) raising T of water by 50 C
Look up the C value for ice and the heat of fusion. You already know the value for liquid water.
To determine the amount of heat energy required for this process, we need to consider the following steps:
1. Calculate the heat energy required to raise the temperature of ice from -10.0°C to 0°C.
2. Calculate the heat energy required to melt the ice at 0°C into water at 0°C.
3. Calculate the heat energy required to raise the temperature of the water from 0°C to 50°C.
Let's break it down step by step:
1. Calculate the heat energy required to raise the temperature of ice from -10.0°C to 0°C:
The specific heat capacity of ice is 2.09 J/g°C.
To convert to kilograms, we multiply the mass of ice by 1000.
The formula to calculate the heat energy is Q = m * c * ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Plugging in the values:
Q1 = (0.1000 kg) * (2.09 J/g°C) * (0°C - (-10.0°C))
2. Calculate the heat energy required to melt the ice at 0°C into water at 0°C:
The heat of fusion for converting ice at 0°C to water at 0°C is 334 J/g.
Plugging in the values:
Q2 = (0.1000 kg) * (334 J/g)
3. Calculate the heat energy required to raise the temperature of water from 0°C to 50°C:
The specific heat capacity of water is 4.18 J/g°C.
Plugging in the values:
Q3 = (0.1000 kg) * (4.18 J/g°C) * (50°C - 0°C)
Finally, to calculate the total heat energy required, we sum up all the values obtained:
Total heat energy = Q1 + Q2 + Q3
Performing the calculations should give you the amount of heat energy required to convert 0.1000kg of ice at -10.0°C into water at 50°C.