Post a New Question


posted by .

A dockworker loading crates on a ship finds that a 20 kg crate, initially at rest on a horizontal surface, requires a 73 N horizontal force to set it in motion. However, after the crate is in motion, a horizontal force of 50 N is required to keep it moving with a constant speed. Find the coefficients of static and kinetic friction between crate and floor. *PLEASE HELP*

  • physics -

    The crate's weight is M g = 196 N

    That is the "normal force" on the surface below.

    Mu-static = 73/196 = ___

    Mu_kinetic = 50/196 = ___

    Review the definitions of static and kinetic friction coefficients.

    This is pretty basic stuff

  • physics -

    I try to looking for this answer but now I think I am a person should answer this question ^^. Ok

    Sum F = ma ( because it get loading the crates )
    Fp - F(fr) = ma
    Fp = ma + F(fr)
    Fp = ma + u(k) mg
    => u(k) = (Fp - ma) / mg ( with ma is 0 )
    so u(k) = 59/ ( 22*9.8) ( because kenetic friction always moving )

    The u(s) you guys can do the same thing , just replace another force number to the equation.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question