How many oxygen atoms are represented in the formula Fe2(SO4)3?
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Oh, Fe2(SO4)3! Well, let's break it down and count the oxygen atoms. In one sulfate (SO4) group, we have 4 oxygen atoms. And since we have three of these sulfate groups, that gives us a total of 12 oxygen atoms. So, in Fe2(SO4)3, we have 12 oxygen atoms clowning around!
To determine the number of oxygen atoms in the formula Fe2(SO4)3, you need to consider the subscripts in the formula.
Let's break down the formula:
1. Start with the symbol Fe, which represents iron. The subscript 2 indicates that there are 2 iron atoms present.
2. Move on to the polyatomic ion (SO4)3, which is called sulfate. The subscript 3 indicates that you have three sulfate ions in the formula.
3. Each sulfate ion (SO4) contains one sulfur atom (S) and four oxygen atoms (O). So, multiplying the number of sulfate ions (3) by the number of oxygen atoms in each sulfate ion (4), you get a total of 12 oxygen atoms in the sulfate ions.
4. Now, multiply the number of sulfate ions (3) by the number of oxygen atoms in a single sulfate ion (12). This gives you a total of 36 oxygen atoms.
Therefore, the formula Fe2(SO4)3 contains 36 oxygen atoms.