the perimeter of a triangle is 64 m, length is 8 m more than twice the width, what is the length
Hmmmm. Since when does a triangle have a length, and a width? Is this a new type of triangle?
Draw a triangle with length ab as 5cm length ac as 4cm and length bc 3cm
To find the length of the triangle, we need to set up and solve an equation based on the given information.
Let's assume that the width of the triangle is "w" meters. According to the problem, the length is 8 meters more than twice the width. So, the length can be represented as "2w + 8" meters.
The perimeter of a triangle is the sum of the lengths of all its sides. In this case, the perimeter is given as 64 meters. For a triangle, the sum of the lengths of all its sides is equal to the perimeter.
Therefore, we can form an equation:
Length + Width + Length = Perimeter
(2w + 8) + w + (2w + 8) = 64
Now, let's solve this equation to find the value of "w," which represents the width of the triangle.
2w + 8 + w + 2w + 8 = 64
5w + 16 = 64
5w = 48
w = 48/5
w = 9.6
Now we have the value of the width, which is approximately 9.6 meters.
To find the length, substitute the width value back into the equation for length:
Length = 2w + 8 = 2(9.6) + 8 = 19.2 + 8 = 27.2
Therefore, the length of the triangle is approximately 27.2 meters.