A pressure cooker with a volume of 6 L is filled with 27 grams of water and heated to 390.2 K. What is the pressure (atm) in the cooker?
Use P=nRT/V
n=27 g /18 g mole^-1
V and T are in the question. You need to find the correct value for R
Laura, you should check your previous posts. I answered this yesterday
http://www.jiskha.com/display.cgi?id=1323138582
Thank you DrBob, I missed that.
Dr Russ
To determine the pressure inside the pressure cooker, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = moles of gas
R = ideal gas constant (0.0821 L·atm/mol·K)
T = absolute temperature (in Kelvin)
First, we need to determine the number of moles of water in the pressure cooker. We can do this by using the molar mass of water, which is 18 g/mol.
27 g of water * (1 mol / 18 g) = 1.5 moles of water
Now, we can calculate the pressure using the ideal gas law equation:
P * 6 L = 1.5 moles * 0.0821 L·atm/mol·K * 390.2 K
Solving for P:
P = (1.5 moles * 0.0821 L·atm/mol·K * 390.2 K) / 6 L
P ≈ 6.11 atm
Therefore, the pressure inside the pressure cooker is approximately 6.11 atm.