calculus
posted by Daniel .
Anti Derivative of
F''(x) = 4 + 6x + 24x^2, f(0) = 3, f(1)=10
Not sure how to find the value of the constant for F'(x).

It is not clear if you want F'(x) or whatever you call f(x).
F'(x) = integral of F"(x)
= 4x + 3x^2 + 8x^3 + C
where C is any constant
F(x) = 2x^2 + x^3 + 2x^4 + Cx + C'
where C' is a different constant.
You could choose C and C' to make F(0) = 3 and F(1) = 10, but the problem does not ask for F(x)
F(0) = 3 = C
F(1) = 2 + 1 + 2 + 3 + C' = 10
C' = 2
F(x) = 2x^2 + x^3 + 2x^4 + 3x + 2