Algebra 2

posted by .

-4x^2-2-3


Put the equation in vertex form and find the vertex

  • Algebra 2 -

    What equation ?

    you posted an algebraic expression which does not even make sense.
    it would simplify to -4x^2 - 5

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra

    Identify the vertex and the axis of symmetry for the graph of y=5(x-2)^2 + 3. a) vertex (2,3); x = -2 b) vertex (-2,-3); x = 2 c) vertex (2,3); x = 2 d) vertex (-2,-3); x = -2 I have no idea how to solve this problem! Please help. …
  2. Algebra

    I have to find the vertex, axis of symmetry, and x intercepts of x^2-x+(5/4). I put it in standard form as -(x+-.5)^2+1.5. Thus, the vertex would be .5, 1.5. But the book's answer is 1/2, 1. How did they get this?
  3. Pre-cal

    Find the vertex of y^2 + 4y + 2x +10 = 0. Use completing the square to put the equation into standard form as your first step. Could you show me how to get the vertex?
  4. Algebra

    Find the equation of the parabola with its vertex at (h,k). Vertex: (-2.1) Focus: (-5,1) I know I put it into (y-k)^2=4(p)(x-h) so (y-1)^2=4(p)(x+2). How do I find the value of p?
  5. Algebra

    Find the equation of the parabola with its vertex at (h,k). Vertex: (-2.1) Focus: (-5,1) I know I put it into (y-k)^2=4(p)(x-h) so (y-1)^2=4(p)(x+2). How do I find the value of p?
  6. Algebra 2

    f(x)=-x^2 - 3x Find the axis of symmetry, vertex, direction it opens, and write the equation in vertex form. If f(x) =x^2 + 2x g(x)= x-9 h(x) = 3x - 2 Find [f o g o h] (-2) Please explain how you got it I'm really confused right now.
  7. Algebra

    For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work. y = -2x2 + 2x +2 -(1/2)y=x^2-x-1 (-1/2)y+1=x^2-x (-1/2)y+1=(x-1/2)^2-14 (-1/2)y=(x-1/2)^2-5/4 y=-2(x-1/2)^2+5/2 …
  8. Algebra

    For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work. y = -2x2 + 2x +2 -(1/2)y = x^2 - x - 1 (-1/2)y + 1 = x^2 - x (-1/2)y + 1 = (x - 1/2)^2 - 1/4 (-1/2)y = (x-1/2)^2 …
  9. Algebra

    Can you please help me with the below question: The vertex of a parabola is located at (-12, -1). The parabola also passes through the point (-10, 5). Write the equation of this parabola in both vertex form and standard form. Vertex …
  10. Algebra2

    Write an equation of an ellipse in standard form with center at the origin and with the given vertex and co-vertex vertex at (-3,0) and co-vertex at (0.2)

More Similar Questions